Optimal. Leaf size=168 \[ \frac{3 a^2 \tanh ^{-1}(\sin (c+d x))}{8 d}+\frac{a^2 \tan (c+d x) \sec ^3(c+d x)}{4 d}+\frac{3 a^2 \tan (c+d x) \sec (c+d x)}{8 d}+\frac{2 a b \sec ^5(c+d x)}{5 d}-\frac{b^2 \tanh ^{-1}(\sin (c+d x))}{16 d}+\frac{b^2 \tan (c+d x) \sec ^5(c+d x)}{6 d}-\frac{b^2 \tan (c+d x) \sec ^3(c+d x)}{24 d}-\frac{b^2 \tan (c+d x) \sec (c+d x)}{16 d} \]
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Rubi [A] time = 0.169557, antiderivative size = 168, normalized size of antiderivative = 1., number of steps used = 11, number of rules used = 6, integrand size = 28, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.214, Rules used = {3090, 3768, 3770, 2606, 30, 2611} \[ \frac{3 a^2 \tanh ^{-1}(\sin (c+d x))}{8 d}+\frac{a^2 \tan (c+d x) \sec ^3(c+d x)}{4 d}+\frac{3 a^2 \tan (c+d x) \sec (c+d x)}{8 d}+\frac{2 a b \sec ^5(c+d x)}{5 d}-\frac{b^2 \tanh ^{-1}(\sin (c+d x))}{16 d}+\frac{b^2 \tan (c+d x) \sec ^5(c+d x)}{6 d}-\frac{b^2 \tan (c+d x) \sec ^3(c+d x)}{24 d}-\frac{b^2 \tan (c+d x) \sec (c+d x)}{16 d} \]
Antiderivative was successfully verified.
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Rule 3090
Rule 3768
Rule 3770
Rule 2606
Rule 30
Rule 2611
Rubi steps
\begin{align*} \int \sec ^7(c+d x) (a \cos (c+d x)+b \sin (c+d x))^2 \, dx &=\int \left (a^2 \sec ^5(c+d x)+2 a b \sec ^5(c+d x) \tan (c+d x)+b^2 \sec ^5(c+d x) \tan ^2(c+d x)\right ) \, dx\\ &=a^2 \int \sec ^5(c+d x) \, dx+(2 a b) \int \sec ^5(c+d x) \tan (c+d x) \, dx+b^2 \int \sec ^5(c+d x) \tan ^2(c+d x) \, dx\\ &=\frac{a^2 \sec ^3(c+d x) \tan (c+d x)}{4 d}+\frac{b^2 \sec ^5(c+d x) \tan (c+d x)}{6 d}+\frac{1}{4} \left (3 a^2\right ) \int \sec ^3(c+d x) \, dx-\frac{1}{6} b^2 \int \sec ^5(c+d x) \, dx+\frac{(2 a b) \operatorname{Subst}\left (\int x^4 \, dx,x,\sec (c+d x)\right )}{d}\\ &=\frac{2 a b \sec ^5(c+d x)}{5 d}+\frac{3 a^2 \sec (c+d x) \tan (c+d x)}{8 d}+\frac{a^2 \sec ^3(c+d x) \tan (c+d x)}{4 d}-\frac{b^2 \sec ^3(c+d x) \tan (c+d x)}{24 d}+\frac{b^2 \sec ^5(c+d x) \tan (c+d x)}{6 d}+\frac{1}{8} \left (3 a^2\right ) \int \sec (c+d x) \, dx-\frac{1}{8} b^2 \int \sec ^3(c+d x) \, dx\\ &=\frac{3 a^2 \tanh ^{-1}(\sin (c+d x))}{8 d}+\frac{2 a b \sec ^5(c+d x)}{5 d}+\frac{3 a^2 \sec (c+d x) \tan (c+d x)}{8 d}-\frac{b^2 \sec (c+d x) \tan (c+d x)}{16 d}+\frac{a^2 \sec ^3(c+d x) \tan (c+d x)}{4 d}-\frac{b^2 \sec ^3(c+d x) \tan (c+d x)}{24 d}+\frac{b^2 \sec ^5(c+d x) \tan (c+d x)}{6 d}-\frac{1}{16} b^2 \int \sec (c+d x) \, dx\\ &=\frac{3 a^2 \tanh ^{-1}(\sin (c+d x))}{8 d}-\frac{b^2 \tanh ^{-1}(\sin (c+d x))}{16 d}+\frac{2 a b \sec ^5(c+d x)}{5 d}+\frac{3 a^2 \sec (c+d x) \tan (c+d x)}{8 d}-\frac{b^2 \sec (c+d x) \tan (c+d x)}{16 d}+\frac{a^2 \sec ^3(c+d x) \tan (c+d x)}{4 d}-\frac{b^2 \sec ^3(c+d x) \tan (c+d x)}{24 d}+\frac{b^2 \sec ^5(c+d x) \tan (c+d x)}{6 d}\\ \end{align*}
Mathematica [A] time = 0.555151, size = 104, normalized size = 0.62 \[ \frac{15 \left (6 a^2-b^2\right ) \tanh ^{-1}(\sin (c+d x))+10 \left (6 a^2-b^2\right ) \tan (c+d x) \sec ^3(c+d x)+15 \left (6 a^2-b^2\right ) \tan (c+d x) \sec (c+d x)+8 b \sec ^5(c+d x) (12 a+5 b \tan (c+d x))}{240 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.11, size = 189, normalized size = 1.1 \begin{align*}{\frac{{a}^{2} \left ( \sec \left ( dx+c \right ) \right ) ^{3}\tan \left ( dx+c \right ) }{4\,d}}+{\frac{3\,{a}^{2}\sec \left ( dx+c \right ) \tan \left ( dx+c \right ) }{8\,d}}+{\frac{3\,{a}^{2}\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{8\,d}}+{\frac{2\,ab}{5\,d \left ( \cos \left ( dx+c \right ) \right ) ^{5}}}+{\frac{{b}^{2} \left ( \sin \left ( dx+c \right ) \right ) ^{3}}{6\,d \left ( \cos \left ( dx+c \right ) \right ) ^{6}}}+{\frac{{b}^{2} \left ( \sin \left ( dx+c \right ) \right ) ^{3}}{8\,d \left ( \cos \left ( dx+c \right ) \right ) ^{4}}}+{\frac{{b}^{2} \left ( \sin \left ( dx+c \right ) \right ) ^{3}}{16\,d \left ( \cos \left ( dx+c \right ) \right ) ^{2}}}+{\frac{{b}^{2}\sin \left ( dx+c \right ) }{16\,d}}-{\frac{{b}^{2}\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{16\,d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.09373, size = 243, normalized size = 1.45 \begin{align*} \frac{5 \, b^{2}{\left (\frac{2 \,{\left (3 \, \sin \left (d x + c\right )^{5} - 8 \, \sin \left (d x + c\right )^{3} - 3 \, \sin \left (d x + c\right )\right )}}{\sin \left (d x + c\right )^{6} - 3 \, \sin \left (d x + c\right )^{4} + 3 \, \sin \left (d x + c\right )^{2} - 1} - 3 \, \log \left (\sin \left (d x + c\right ) + 1\right ) + 3 \, \log \left (\sin \left (d x + c\right ) - 1\right )\right )} - 30 \, a^{2}{\left (\frac{2 \,{\left (3 \, \sin \left (d x + c\right )^{3} - 5 \, \sin \left (d x + c\right )\right )}}{\sin \left (d x + c\right )^{4} - 2 \, \sin \left (d x + c\right )^{2} + 1} - 3 \, \log \left (\sin \left (d x + c\right ) + 1\right ) + 3 \, \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + \frac{192 \, a b}{\cos \left (d x + c\right )^{5}}}{480 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 0.525928, size = 343, normalized size = 2.04 \begin{align*} \frac{15 \,{\left (6 \, a^{2} - b^{2}\right )} \cos \left (d x + c\right )^{6} \log \left (\sin \left (d x + c\right ) + 1\right ) - 15 \,{\left (6 \, a^{2} - b^{2}\right )} \cos \left (d x + c\right )^{6} \log \left (-\sin \left (d x + c\right ) + 1\right ) + 192 \, a b \cos \left (d x + c\right ) + 10 \,{\left (3 \,{\left (6 \, a^{2} - b^{2}\right )} \cos \left (d x + c\right )^{4} + 2 \,{\left (6 \, a^{2} - b^{2}\right )} \cos \left (d x + c\right )^{2} + 8 \, b^{2}\right )} \sin \left (d x + c\right )}{480 \, d \cos \left (d x + c\right )^{6}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.20809, size = 463, normalized size = 2.76 \begin{align*} \frac{15 \,{\left (6 \, a^{2} - b^{2}\right )} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 1 \right |}\right ) - 15 \,{\left (6 \, a^{2} - b^{2}\right )} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 1 \right |}\right ) + \frac{2 \,{\left (150 \, a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{11} + 15 \, b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{11} - 480 \, a b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{10} - 210 \, a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{9} + 235 \, b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{9} + 480 \, a b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{8} + 60 \, a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{7} + 390 \, b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{7} - 960 \, a b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{6} + 60 \, a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} + 390 \, b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} + 960 \, a b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{4} - 210 \, a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} + 235 \, b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 96 \, a b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + 150 \, a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 15 \, b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 96 \, a b\right )}}{{\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 1\right )}^{6}}}{240 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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